x^2+2y^2+3xy=

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Solution for x^2+2y^2+3xy= equation:


Simplifying
x2 + 2y2 + 3xy = 0

Reorder the terms:
3xy + x2 + 2y2 = 0

Solving
3xy + x2 + 2y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(x + y)(x + 2y) = 0

Subproblem 1

Set the factor '(x + y)' equal to zero and attempt to solve: Simplifying x + y = 0 Solving x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 x + 0 = 0 + -1y x = 0 + -1y Remove the zero: x = -1y Simplifying x = -1y

Subproblem 2

Set the factor '(x + 2y)' equal to zero and attempt to solve: Simplifying x + 2y = 0 Solving x + 2y = 0 Move all terms containing x to the left, all other terms to the right. Add '-2y' to each side of the equation. x + 2y + -2y = 0 + -2y Combine like terms: 2y + -2y = 0 x + 0 = 0 + -2y x = 0 + -2y Remove the zero: x = -2y Simplifying x = -2y

Solution

x = {-1y, -2y}

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